Question -
Answer -
Let AB be the line segment between the axes such that point R (h, k) divides AB in the ratio 1: 2.
Let the respective coordinates of A and B be (x, 0) and (0, y).
Since point R (h, k) divides AB in the ratio 1: 2, according to the section formula,
Therefore, the respective coordinates of A and B are
and (0, 3k).Now, the equation of line AB passing through points
and (0, 3k) isThus,the required equation of the line is 2kx + hy = 3hk.