Question -
Answer -
Let the given point be A (-2, -1) , B (4, 0) , C ( 3, 3) and D (-3, 2)
So now, The slope of AB = (0+1)/(4+2) = 1/6
The slope of CD = (3-2)/(3+3) = 1/6
Hence, slope of AB = Slope of CD
∴AB ∥ CD
Now,
The slope of BC = (3-0)/(3-4) = 3/-1 = -3
The slope of AD = (2+1)/(-3+2) = 3/-1 = -3
Hence, slope of BC = Slope of AD
∴ BC ∥ AD
Thus the pair of opposite sides are quadrilateralare parallel, so we can say that ABCD is a parallelogram.
Hence the given vertices, A (-2, -1), B (4, 0), C(3, 3) andD(-3, 2) are vertices of a parallelogram.