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Question -

Draw a quadrilateral in the Cartesian plane, whose vertices are (–4, 5), (0, 7), (5, –5) and (–4, –2). Also, find its area.



Answer -

Let ABCD be the given quadrilateral with vertices A (–4, 5), B (0, 7), C (5, –5), and D (–4, –2).
Then, by plotting A, B, C, and D on the Cartesian plane and joining AB, BC, CD, and DA, the given quadrilateral can be drawn as

To find the area ofquadrilateral ABCD, we draw one diagonal, say AC.

Accordingly, area (ABCD)= area (ΔABC) + area (ΔACD)

We know that the area ofa triangle whose vertices are (x1y1),(x2y2), and (x3y3)is 

Therefore, area of ΔABC

Area of ΔACD

Thus, area (ABCD)

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