Question -
Answer -
AB, CD and EF intersect at O. Such that OF is the bisector of
тИаBOD тИаBOF = 35┬░
┬а
тИ╡ OF bisects тИаBOD,
тИ┤ тИаDOF = тИаBOF = 35┬░ (Vertically opposite angles)
тИ┤ тИаBOD = 35┬░ + 35┬░ = 70┬░
But тИаBOC + тИаBOD = 180┬░ (Linear pair)
тЗТ тИаBOC + 70┬░ = 180┬░
тЗТ тИаBOC = 180┬░-70┬░= 110┬░
But тИаAOD = тИаBOC (Vertically opposite angles)
= 110┬░
Hence тИаBOC = 110┬░ and тИаAOD =110┬░