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Question -

An angle is 14┬░ more than its complementary angle. What is its measure?



Answer -

Let required angle = x
Then its complementary angle = 90┬░ тАУ x
тИ┤┬а x + 14┬░ = 90┬░ тАУ x
x + x = 90┬░ тАУ 14┬░ тЗТ┬а 2x = 76┬░
тЗТ x =┬а= 38┬░
тИ┤┬а Required angle = 38┬░

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