Question -
Answer -
PA and PB are the tangents drawn from a point P out side the circle with centre O
CD is another tangents to the circle at point E which intersects PA and PB at C and D respectively
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PA = 14 cm
PA and PB are the tangents to the circle from P
PA = PB = 14 cm
Now CA and CE are the tangents from C
CA = CE тАж.(i)
Similarly DB and DE are the tangents from D
DB = DE тАж.(ii)
Now perimeter of тИЖPCD
= PC + PD + CD
= PC + PD + CE + DE
= PC + CE + PD + DE
= PC + CA + PD = DB {From (i) and (ii)}
= PA + PB
= 14 + 14
= 28 cm