Question -
Answer -
Consider the followingdiagram
In ╬ФPOOтАЩ and ╬ФQOOтАЩ
OP = OQ┬а┬а┬а┬а┬а┬а┬а┬а┬а(Radius of circle 1)
OтАЩP = OтАЩQ┬а┬а┬а┬а┬а┬а┬а(Radius of circle 2)
OOтАЩ = OOтАЩ┬а┬а┬а┬а┬а┬а┬а(Common arm)
So, by SSS congruency,╬ФPOOтАЩ тЙЕ ╬ФQOOтАЩ
Thus, тИаOPOтАЩ = тИаOQOтАЩ (proved).