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Question -

Two circlesintersect at two points B and C. Through B, two line segments ABD and PBQ aredrawn to intersect the circles at A, D and P, Q respectively (see the givenfigure). Prove that ACP = QCD.



Answer -

Join chordsAP and DQ.

For chord AP,

PBA = ACP (Angles in the same segment) … (1)

For chord DQ,

DBQ = QCD (Angles in the same segment) … (2)

ABD and PBQ are line segments intersecting at B.

PBA = DBQ (Vertically opposite angles) … (3)

From equations (1), (2), and (3), we obtain

ACP = QCD

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