Question -
Answer -
then ∠PTQ is equal to
(A) 60° (B) 70°
(C) 80° (D) 90°
Answer:
From the question, it is clear that OP is theradius of the circle to the tangent PT and OQ is the radius to the tangents TQ.
So, OP ⊥ PT and TQ ⊥ OQ
∴∠OPT = ∠OQT = 90°
Now, in the quadrilateral POQT, we know thatthe sum of the interior angles is 360°
So, ∠PTQ+∠POQ+∠OPT+∠OQT = 360°
Now, by putting the respective values we get,
∠PTQ +90°+110°+90° = 360°
∠PTQ = 70°
So, ∠PTQ is 70° which isoption B.