Question -
Answer -
(i)┬а{A,P, L, E}┬атЗФ┬а{x:x is a letter of word тАЬAPPLEтАЭ}
(ii)┬а{5,-5}┬атЗФ┬а{x:x2┬атАУ 25 =0}
The solution set of x2┬атАУ25 = 0 is x = ┬▒5
(iii)┬а{0}┬атЗФ┬а{x:x+5=5, x тИИ┬аz}
The solution set of x + 5 = 5 is x = 0.
(iv)┬а{1,2, 5, 10}┬атЗФ┬а{x: x is a natural and divisor of 10}
The natural numbers which are divisor of 10 are 1, 2, 5, 10.
(v)┬а{A,H, J, R, S, T, N}┬атЗФ┬а{x: x is a letter of the word тАЬRAJASTHANтАЭ}
The distinct letters of word тАЬRAJASTHANтАЭ are A, H, J, R, S, T, N.
(vi)┬а{2,5}┬атЗФ┬а{x:x is a prime natural number and a divisor of 10}
The prime natural numbers which are divisor of 10 are 2, 5.