Question -
Answer -
(i) Consider R1
Given R1 = {(a, a), (a, b), (a, c), (b, b), (b, c), (c, a), (c,b), (c, c)}
Now we have check R1 isreflexive, symmetric and transitive
Reflexive:
Given (a, a), (b, b)and (c, c) ∈ R1
So, R1 isreflexive.
Symmetric:
We see that the ordered pairs obtained by interchanging the components of R1 arealso in R1.
So, R1 is symmetric.
Transitive:
Here, (a, b) ∈R1, (b, c)∈R1 and also (a, c)∈R1
So, R1 istransitive.
(ii) Consider R2
Given R2 ={(a, a)}
Reflexive:
Clearly (a,a) ∈R2.
So, R2 isreflexive.
Symmetric:
Clearly (a,a) ∈R
⇒ (a, a) ∈R.
So, R2 issymmetric.
Transitive:
R2 isclearly a transitive relation, since there is only one element in it.
(iii) Consider R3
Given R3 = {(b, c)}
Reflexive:
Here,(b, b)∉ R3 neither (c, c) ∉ R3
So, R3 isnot reflexive.
Symmetric:
Here, (b, c) ∈R3, but (c,b) ∉R3
So, R3 isnot symmetric.
Transitive:
Here, R3 has only two elements.
Hence, R3 istransitive.
(iv) Consider R4
Given R4 = {(a, b), (b, c), (c, a)}.
Reflexive:
Here, (a, a) ∉ R4, (b, b)∉ R4 (c, c)∉ R4
So, R4 is not reflexive.
Symmetric:
Here, (a, b) ∈ R4, but (b,a) ∉ R4.
So, R4 is not symmetric
Transitive:
Here, (a, b) ∈R4, (b, c)∈R4, but (a, c)∉R4
So, R4 is not transitive.