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Chapter 1 Relations and Functions Ex 1.4 Solutions

Question - 11 : - LetA=N x N and * be the binary operation on A defined by (a,b)*(c,d)=(a+c,b+d)
Show that * is commutative and associative. Find theidentity element for * on A, if any.

Answer - 11 : -

A= N x N Binary operation * is defined as (a, b) * (c, d) = (a + c, b + d)
(a) Now (c, d) * (a,b) = (c+a, d+b) = (a+c,b+d)
=> (a, b) * (c, d) = (c, d) * (a, b)
This operation * is commutative

(b) Next(a,b)* [(c,d)*(e,f)]=(a,b)*(c+e,d+f) = ((a + c + e), (b + d + f))
and [(a, b) * (c, d)] * (e, f)=(a+c, b+d) * (e, f) = ((a + c + e, b+d + f))
=> (a, b) * [(c, d) * (e, f)] = [(a, b) * (c, d)] * (e,f)
The binary operation given is associative

(c) Identity element does not exists.

Question - 12 : - Statewhether the following statements are true or false. Justify.
(i) For an arbitrary binary operation * on a set N,
a*a=a
aN.
(ii) If * is a commutative binary operation on N,then
a * (b * c) = (c * b) * a

Answer - 12 : -

(i)A binary operation on N is defined as
a*a=a
aN.
Here operation * is not defined.
Given statement is false.

(ii) * is a binary commutative operation on N. c
* b = b * c
* is commutative
(c * b) * a = (b * c) * a = a * (b * c)
Thus a * (b * c) = (c * b) * a
This statement is true.

Question - 13 : - Considera binary operation * on N defined as a * b = a³ + b³. Choose the correctanswer.

Answer - 13 : - (a) Is * both associative and commutative?
(b) Is * commutative but not associative?
(c) Is * associative but not commutative?
(d) Is * neither commutative nor associative?


Solution


On N, the operation *is defined as * b = a3 + b3.

For, ab, N, we have:

* b = a3 + b3 = b3 + a3 = * a [Addition is commutative in N]

Therefore,the operation * is commutative.

Itcan be observed that:

(1 * 2) * 3 ≠ 1 * (2 * 3) ; where 1, 2, 3  N

Therefore,the operation * is not associative.

Hence,the operation * is commutative, but not associative. Thus, the correct answeris B.

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