The Total solution for NCERT class 6-12
If the HCF of 65 and 117 is expressible in theform 65m – 117, then the value of m is
(A) 4 (B) 2
(C) 1 (D) 3
Solution:
(B) 2
Explanation:
Let us find the HCF of 65 and 117,
117 = 1×65 + 52
65 = 1× 52 + 13
52 = 4 ×13 + 0
Hence, we get the HCF of 65 and 117 = 13.
According to the question,
65m – 117 = 13
65m = 117+13 = 130
∴ m =130/65 = 2
Hence, option (B) is thecorrect answer.