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Question 1 :

Compute theindicated products:

Answer 1 :

(i) Consider

On simplification we get,

(ii) Consider

On simplification we get,

(iii) Consider

On simplification we get,

Question 2 :

Show that AB ≠ BAin each of the following cases:

Answer 2 :

(i) Consider,

Again consider,

From equation (1) and (2), it is clear that

AB ≠ BA

(ii) Consider,

Now again consider,

From equation (1) and (2), it is clear that

AB ≠ BA

(iii) Consider,

Now again consider,

From equation (1) and (2), it is clear that

AB ≠ BA

Question 3 :

Compute theproducts AB and BA whichever exists in each of the following cases:

Answer 3 :

(i) Consider,

BA does not exist

Because the number of columns in B is greater than the rows in A

(ii) Consider,

Again consider,

(iii) Consider,

AB = [0 + (-1) + 6 + 6]

AB = 11

Again consider,

(iv) Consider,

Question 4 :

Show that AB ≠ BAin each of the following cases:

Answer 4 :

(i) Consider,

Again consider,

From equation (1) and (2), it is clear that

AB ≠ BA

(ii) Consider,

Again consider,

From equation (1) and (2) it is clear that,

AB ≠ BA

Question 5 : Evaluate the following:

Answer 5 :

1.

2.

3.

Question 6 :

Answer 6 :


Question 7 :

Answer 7 :


Question 8 :

Answer 8 :


Question 9 :

Answer 9 :


Question 10 :

Answer 10 :


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