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RD Chapter 5 Factorisation of Algebraic Expressions Ex 5.4 Solutions

Question - 11 : -

Answer - 11 : -


Question - 12 : - (a – 3b)3 + (3b – c)3 + (c – a)3

Answer - 12 : -

(a- 3b)3 + (3b – c)3 + (c – a)3
∵ a – 3b+ 3b – c + c – a = 0
∴ (a – 3b)3 + (3b – c)3 + (c – a)3
= 3(a – 3b) (3b – c) (c – a)                      {∵ a3 + b3 + c3 =3abc if a + b + c = 0}

Question - 13 : -

Answer - 13 : -


Question - 14 : -

Answer - 14 : -


Question - 15 : - 2 2–√ a3+ 162–√ b3 + c3 – 12abc

Answer - 15 : -

Question - 16 : - Find the value of x3 + y3 – 12xy + 64, when x + y = -4

Answer - 16 : -

x3 + y3 – 12xy + 64
x + y = -4
Cubing both sides,
x3 + y3 + 3 xy(x + y) = -64
Substitute the value of (x + y)
⇒ x2 +y2 + 3xy x (-4) = -64
⇒ x3 + y2 – 12xy + 64 = 0

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