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RD Chapter 4 Algebraic Identities Ex VSAQS Solutions

Question - 1 : -

Answer - 1 : -


Question - 2 : -

Answer - 2 : -


Question - 3 : - If a + b = 7 and ab = 12, find the value of a2 + b2.

Answer - 3 : -

a + b = 7, ab = 12
Squaring both sides,
(a + b)2 = (7)2
 a2 + b2 + 2ab = 49
 a2 + b2 + 2 x 12 = 49
a2 +b2 + 24 = 49
a2 +b2 = 49 – 24 = 25
a2 +b2 = 25

Question - 4 : - If a – b = 5 and ab = 12, find the value of a2 + b2 .

Answer - 4 : -

a – b = 5, ab = 12
Squaring both sides,
(a –b)= (5)2
 a2 + b2 – 2ab = 25
 a2 + b2 – 2 x 12 = 25
 a2 + b2 – 24 = 25
 a2 + b2 = 25 + 24 = 49
a2 +b2 = 49

Question - 5 : -

Answer - 5 : -


Question - 6 : -

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Question - 7 : -

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