Solution:
The radius of 1st circle, r1 =21/2 cm (as diameter D is given as 21 cm)
So, area of gold region = π r12 =π(10.5)2 = 346.5 cm2
Now, it is given that each of the other bandsis 10.5 cm wide,
So, the radius of 2nd circle,r2 = 10.5cm+10.5cm = 21 cm
Thus,
∴ Area of red region = Area of 2nd circle − Areaof gold region = (πr22−346.5) cm2
= (π(21)2 − 346.5) cm2
= 1386 − 346.5
= 1039.5 cm2
Similarly,
The radius of 3rd circle, r3 =21 cm+10.5 cm = 31.5 cm
The radius of 4th circle, r4 =31.5 cm+10.5 cm = 42 cm
The Radius of 5th circle, r5 =42 cm+10.5 cm = 52.5 cm
For the area of nth region,
A = Area of circle n – Area of circle (n-1)
∴ Area of blue region (n=3) = Area of third circle – Area ofsecond circle
= π(31.5)2 – 1386 cm2
= 3118.5 – 1386 cm2
= 1732.5 cm2
∴ Area of black region (n=4) = Area of fourth circle – Area ofthird circle
= π(42)2 – 1386 cm2
= 5544 – 3118.5 cm2
= 2425.5 cm2
∴ Area of white region (n=5) = Area of fifth circle – Area offourth circle
= π(52.5)2 – 5544 cm2
= 8662.5 – 5544 cm2
= 3118.5 cm2