The Total solution for NCERT class 6-12
Answer - 1 : -
(i) 4a – 12हल :4a – 12= 4 (a-3)
(ii) ac – be + c + cbहल :ac – bc + c + cb= (a – b + c + b)= c (a + c)
(iii) 36P +45 Pहल :36P + 45P3(4 + 5P2)
(iv) y2 –8ayहल :y2 – 8ay = 9P= y(y – 8a)
(v) 7a +7bहल :7a + 7b= 7(a + b)
(vi) 3a3x –45a2x – 18aहल :3a3x – 45a2x –18a= 3a(a – 15ax – 6)
Answer - 2 : -
Answer - 3 : -
(i) xy (z2 +a2)- x2za – y2za
हल := xy (z2 + a2) – x2za –y2za= xyz2 + xya2 –x2za – y2za= xyz2 – x2za +xya2 – y2za= xy(yz – xa) + ya(xa – yz)(yz – xa) (xy – ya)
(ii). p3 +p + q – 1 – p2 – pqहल :p3 + p + q – 1 – p2 –pq= p3 – pq + p – p2 +q – 1= p(p2 – q + 1) – 1(p2 –q + 1)= (p2 – q + 1) (p – 1)
(iii). 2ab2 –aby + 2cby – cy2हल :2ab2 – aby + 2cby – cy2= 2ab2 – aby + 2cby – cy2= ab(2b – y) + cy (2b – y)= (2b – y) (ab + cy)
(vi) x2 +y3 +xy (y + 1)हल :x2 + y3 +xy(y + 1)= x2+ y3 + xy + xy= x2 + xy + xy2 +y3= x(x +y) + y2(x +y)= (x + y) (x + y2)
Answer - 4 : -
(i) 23 x72 +77 x 72हल :23 × 72 + 77 × 72= 72(23 + 77)= 72 × 100 = 7200
(ii) 56 × 25 – 25 × 39 – 25 × 17हल :56 × 25 – 25 × 39 – 25 × 1725(56 – 39 – 17)= 25 × (56 – 56)= 25 × 0 = 0
(iii) 27 × 47 + 55 × 8 + 27 × 53 + 45 × 8हल :27 × 47 + 55 × 8 + 27 × 53 + 45 × 8= 27 × 47 + 27 × 53 + 55 × 8 + 45 × 8= 27 × (47 + 53) + 8(55 + 45)= 27 × 100 + 8 × 100= 2700 + 800 = 3500