The Total solution for NCERT class 6-12
Answer - 1 : -
Answer - 2 : -
Answer - 3 : -
Answer - 4 : - f(x) = x3 +13x2 + 32x + 20One zero = -2 or x = -2x + 2 is a factor of f (x)Now dividing f(x) by x + 2, we get
x + 1 = 0 => x = -1and x + 10 = 0=> x = -10-1 and -10Hence zeros are -10, -1, -2
Answer - 5 : -
Answer - 6 : -
Answer - 7 : -
Either x + 6 = 0, then x = -6or x – 5 = 0, then x = 5Hence other two zeros are -6, 5and all zeros are 2, -2, -6, 5
Answer - 8 : -
Answer - 9 : - Let f(x) = 2x3 +x2 – 6x – 3and two zeros of f(x) are – √3 and √3
Answer - 10 : -