The Total solution for NCERT class 6-12
Answer - 1 : -
(i) 26 = 2 × 2 ×2 × 2 × 2 × 2 = 64(ii) 93 = 9 × 9 × 9 = 729(iii) 112 = 11 × 11 = 121(iv) 54 = 5 × 5 × 5 × 5 = 625
Answer - 2 : -
(i) 6 × 6 × 6 × 6 = 63(ii) t × t = t2(iii) b × b × b × b = b4(iv) 5 × 5× 7 × 7 × 7 = 52 × 73 = 52 ·73(v) 2 × 2 × a × a = 22 × a2 = 22 ·a2(vi) a × a ×a × c × c × c × c × d = a3 ×c4 × d = a3 ·c4 · d
Answer - 3 : -
Answer - 4 : -
(i) 43 or 3443 = 4 × 4 × 4 = 64,34 = 3 × 3 × 3 × 3 = 81Since 81 > 64∴ 34 isgreater than 43.
(ii) 53 or 3553 = 5 × 5 × 5 = 12535 = 3 × 3 × 3 × 3 × 3 = 243Since 243 > 125∴ 35 isgreater than 53.
(iii) 28 or 8228 =2 × 2 × 2 × 2 × 2 × 2 × 2 ×2 = 25682 = 8 × 8 = 64Since 256 > 64∴ 28 isgreater than 28.
(iv) 1002 or 21001002 = 100 × 100 = 100002100 = 2 × 2 × 2 × … 100 timesHere 2 × 2 × 2 ×2 × 2 × 2 × 2 ×2 × 2 × 2 × 2 × 2 × 2 × 2 = 214 = 16384Since 16384 > 10,000∴ 2100is greater than 1002.
(v) 210 or 102210 = 2 × 2 × 2 × 2 × 2 × 2 × 2× 2 × 2 × 2 = 1024102 = 10 × 10 = 100Since 1024 > 100∴ 210 isgreater than 102.
Answer - 5 : -
Answer - 6 : -
(i) 2 × 103 = 2 ×10 × 10 × 10 = = 2000(ii) 72 × 22 = = 7 × 7 × 2 × 2 = 196(iii) 23 × 5 = 2 × 2 × 2 × 5 = 40(iv) 3 × 44 = 3 × 4 × 4 × 4 × 4= 768(v) 0 × 102 = 0 × 10 × 10 = = 0(vi) 52 × 33 = 5 × 5 × 3 × 3 × 3 = 675(vii) 24 × 32 = 2 × 2 × 2 × 2 × 3 × 3 = 144(viii) 32 × 104 = 3 × 3 × 10 × 10 × 10 × 10 = 90000
Answer - 7 : -
(i) (-4)2 = (-4)× (-4) × (-4) = -64 [∵ (-a)odd number = -aoddnumber](ii) (-3) × (-2)3 = (-3) × (-2)× (-2) × (-2)= (-3) × (-8) = 24(iii) (-3)2 × (-5)2 = [(-3) × (-5)]2= 152 = 225 [∵ am ×bm = (ab)m)(iv) (-2)3 × (-10)3 = [(-2) × (-10)]3= 202 = 8000 [∵ am ×bm = (ab)m]
Answer - 8 : -
(i) 2.7 × 1012; 1.5 ×108Here, 1012 > 108∴ 2.7 ×1012> 1.5 × 108(ii) 4 × 1014; 3 × 1017Here, 1017 > 1014∴ 4 × 1014 < 3 × 1017