The Total solution for NCERT class 6-12
x3 + y3 – 12xy + 64x + y = -4Cubing both sides,x3 + y3 + 3 xy(x + y) = -64Substitute the value of (x + y)⇒ x2 +y2 + 3xy x (-4) = -64⇒ x3 + y2 – 12xy + 64 = 0