Question -
Answer -
Given:
(2x + 3)/4 – 3 < (x – 4)/3 – 2
Add 3 on both sides we get,
(2x + 3)/4 – 3 + 3 < (x – 4)/3 – 2 + 3
(2x + 3)/4 < (x – 4)/3 + 1
(2x + 3)/4 < (x – 4 + 3)/3
(2x + 3)/4 < (x – 1)/3
Cross multiply we get,
3 (2x + 3) < 4 (x – 1)
6x + 9 < 4x – 4
6x + 9 – 9 < 4x – 4 – 9
6x < 4x – 13
6x – 4x < 4x – 13 – 4x
2x < –13
Divide both sides by 2, we get
2x/2 < -13/2
x < -13/2
∴ The solution of the given inequation is (-∞, -13/2).