The Total solution for NCERT class 6-12
The amplitude of the magneticfield part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is the amplitude of the electricfield part of the wave?
Amplitude of magnetic field of anelectromagnetic wave in a vacuum,
B0 =510 nT = 510 × 10−9 T
Speed oflight in a vacuum, c = 3 × 108 m/s
Amplitudeof electric field of the electromagnetic wave is given by the relation,
E = cB0
= 3 × 108 × 510 × 10−9 =153 N/C