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Question -

In Exercises 7.3 and 7.4, what isthe net power absorbed by each circuit over a complete cycle. Explain youranswer.



Answer -

In the inductive circuit,

Rms value of current, I =15.92 A

Rms value of voltage, V =220 V

Hence, the net power absorbed canbe obtained by the relation,

P = VI cos Φ

Where,

Φ = Phase differencebetween V and I

For a pure inductive circuit, thephase difference between alternating voltage and current is 90° i.e., Φ=90°.

Hence, P = 0i.e., the net power is zero.

In the capacitive circuit,

Rms value of current, I =2.49 A

Rms value of voltage, V =110 V

Hence, the net power absorbed canve obtained as:

P = VI Cos Φ

For a pure capacitive circuit,the phase difference between alternating voltage and current is 90° i.e., Φ=90°.

Hence, P = 0i.e., the net power is zero.

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