The Total solution for NCERT class 6-12
If the solenoid inExercise 5.5 is free to turn about the vertical direction and a uniformhorizontal magnetic field of 0.25 T is applied, what is the magnitude of torqueon the solenoid when its axis makes an angle of 30° with the direction ofapplied field?
Magnetic field strength, B =0.25 T
Magnetic moment, M =0.6 T−1
The angle θ,between the axis of the solenoid and the direction of the applied field is 30°.
Therefore, the torqueacting on the solenoid is given as: