Question -
Answer -
Length of a side of the squarecoil, l = 10 cm = 0.1 m
Current flowing in thecoil, I = 12 A
Number of turns on thecoil, n = 20
Angle made by the plane of thecoil with magnetic field, θ = 30°
Strength of magnetic field, B =0.80 T
Magnitude of the magnetic torqueexperienced by the coil in the magnetic field is given by the relation,
τ = n BIA sinθ
Where,
A =Area of the square coil
l × l = 0.1 ×0.1 = 0.01 m2
∴ τ = 20 × 0.8 × 12 × 0.01 × sin30°
= 0.96 N m
Hence, the magnitude of thetorque experienced by the coil is 0.96 N m.