Question -
Answer -
Number of turns on the circularcoil, n = 100
Radius of each turn, r =8.0 cm = 0.08 m
Current flowing in thecoil, I = 0.4 A
Magnitude of the magnetic fieldat the centre of the coil is given by the relation,
Where,
= Permeability of freespace
= 4π × 10–7 T m A–1
Hence, the magnitude of themagnetic field is 3.14 × 10–4 T.