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Question -

A 4 ┬╡F capacitor is charged by a 200 Vsupply. It is then disconnected from the supply, and is connected to anotheruncharged 2 ┬╡F capacitor. How much electrostatic energy of the first capacitoris lost in the form of heat and electromagnetic radiation?



Answer -

Capacitance of a chargedcapacitor,┬а

Supply voltage,┬аV1┬а=200 V

Electrostatic energy stored in┬аC1┬аisgiven by,

Capacitance of an unchargedcapacitor,┬а

When┬аC2┬аisconnected to the circuit, the potential acquired by it is┬аV2.

According to the conservation of charge,initial charge on capacitor┬аC1┬аis equal to thefinal charge on capacitors,┬аC1┬аand┬аC2.

Electrostatic energy for the combination of twocapacitors is given by,

Hence, amount of electrostatic energy lostby capacitor┬аC1

=┬аE1┬атИТ┬аE2

= 0.08 тИТ 0.0533 = 0.0267

= 2.67 ├Ч 10тИТ2┬аJ

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