Question -
Answer -
Length of the wire, l =3 cm = 0.03 m
Current flowing in thewire, I = 10 A
Magnetic field, B =0.27 T
Angle between the current andmagnetic field, θ = 90°
Magnetic force exerted on thewire is given as:
F = BIlsinθ
= 0.27 × 10 × 0.03 sin90°
= 8.1 × 10–2 N
Hence, the magnetic force on thewire is 8.1 × 10–2 N. The direction of the force can beobtained from Fleming’s left hand rule.