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Question -

The resistance of a conductivitycell containing 0.001M KCl solution at 298 K is 1500 Ω. What is the cellconstant if conductivity of 0.001M KCl solution at 298 K is 0.146 × 10−3 Scm−1.



Answer -

Given,

Conductivity, κ =0.146 × 10−3 S cm−1

Resistance, R =1500 Ω

 Cell constant = κ × R

= 0.146 × 10−3 ×1500

=0.219 cm−1

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