Question -
Answer -
(i) Propene→ Propan-2-ol
(ii) Benzylchloride → Benzyl alcohol
(iii) Ethylmagnesium chloride → Propan-1-ol.
(iv) Methylmagnesium bromide → 2-Methylpropan-2-ol.
Answer
(i) Ifpropene is allowed to react with water in the presence of an acid as acatalyst, then propan-2-ol is obtained.
(ii) Ifbenzyl chloride is treated with NaOH (followed by acidification) then benzylalcohol is produced.
(iii) Whenethyl magnesium chloride is treated with methanal, an adduct is the producedwhich gives propan-1-ol on hydrolysis.
(iv) Whenmethyl magnesium bromide is treated with propane, an adduct is the productwhich gives 2-methylpropane-2-ol on hydrolysis.
