The Total solution for NCERT class 6-12
The farthest objects in our Universe discovered by modernastronomers are so distant that light emitted by them takes billions of yearsto reach the Earth. These objects (known as quasars) have many puzzlingfeatures, which have not yet been satisfactorily explained. What is thedistance in km of a quasar from which light takes 3.0 billion years to reachus?
Answer - 31 : -
Time taken by quasar light to reach Earth = 3 billion years
= 3 × 109 years
= 3 × 109 × 365 × 24 × 60 × 60 s
Speed of light = 3 × 108 m/s
Distance between the Earth and quasar
= (3 × 108) × (3 × 109 × 365 × 24 × 60× 60)
= 283824 × 1020 m
= 2.8 × 1022 km
It is a well known fact that during a total solar eclipse the diskof the moon almost completely covers the disk of the Sun. From this fact andfrom the information you can gather from examples 2.3 and 2.4, determine theapproximate diameter of the moon.
Answer - 32 : -
The position of the Sun, Moon, and Earth during a lunar eclipse isshown in the given figure.
Distance of the Moon from the Earth = 3.84 × 108 m
Distance of the Sun from the Earth = 1.496 × 1011 m
Diameter of the Sun = 1.39 × 109 m
It can be observed that ΔTRS and ΔTPQ are similar. Hence, it canbe written as:
Hence, the diameter of the Moon is 3.57× 106 m.
Answer - 33 : -
One relation consists of some fundamental constants that give theage of the Universe by:
Where,
t = Age of Universe
e = Charge of electrons = 1.6 ×10–19 C
= Absolute permittivity
= Mass of protons = 1.67 × 10–27 kg
= Mass of electrons = 9.1 × 10–31 kg
c = Speed of light = 3 × 108 m/s
G = Universal gravitational constant = 6.67 × 1011 Nm2 kg–2
Also,Nm2/C2
Substituting these values in the equation, we get