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Question -

(a) It is known that density ρ of air decreaseswith height as 

Where 1.25 kg m–3 isthe density at sea level, and y0 is a constant.This density variation is called the law of atmospheres. Obtain this lawassuming that the temperature of atmosphere remains a constant (isothermalconditions). Also assume that the value of gremains constant.

(b) A large He balloon of volume 1425 m3 is usedto lift a payload of 400 kg. Assume that the balloon maintains constant radiusas it rises. How high does it rise?

[Take y0= 8000 m and = 0.18 kg m–3].



Answer -

(a) Volume of theballoon, V = 1425 m3

Mass of the payload, m = 400 kg

Acceleration due to gravity, g = 9.8 m/s2

Density of the balloon = ρ

Height to which the balloon rises = y

Density (ρ) of air decreases with height (y) as:

This density variation is called the law of atmospherics.

It can be inferred from equation (i) that the rate ofdecrease of density with height is directly proportional to ρ,i.e.,

Where, k is the constant of proportionality

Height changes from 0 to y, while density changesfrom to ρ.

Integrating the sides between these limits, we get:

(b)

Hence, the balloon will rise to a height of 8 km.

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