Question -
Answer -
Diameter of the first bore, d1 = 3.0mm = 3 × 10–3 m
Diameter of the second bore, = 6.0 mm
Surface tension of water, s = 7.3 × 10–2 Nm–1
Angle of contact between the bore surface and water, θ=0
Density of water, ρ =1.0 × 103 kg/m–3
Acceleration due to gravity, g = 9.8 m/s2
Let h1 and h2 bethe heights to which water rises in the first and second tubes respectively.These heights are given by the relations:
The difference between the levels of water in the two limbs of thetube can be calculated as:
Hence, the difference between levels of water in the two bores is4.97 mm.