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Question -

Two bodies of masses 10 kg and 20 kgrespectively kept on a smooth, horizontal surface are tied to the ends of alight string. A horizontal force F = 600 N is applied to (i)A, (ii) B along the direction of string. What is the tension in the string ineach case?



Answer -

Horizontal force, F = 600 N

Mass of body A, m1 =10 kg

Mass of body B, m2 =20 kg

Total mass of the system, m = m1 + m2 =30 kg

Using Newton’s second law of motion, theacceleration (a) produced in the system can be calculated as:

F = ma

When force F is applied onbody A:

Theequation of motion can be written as:

F – T m1a

T = F – m1a

= 600 – 10 × 20 = 400 N … (i)

When force F is applied onbody B:

Theequation of motion can be written as:

F – T = m2a

T = F – m2a

T = 600 – 20 × 20 = 200 N … (ii)

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