Question -
Answer -
Initial speed of the three-wheeler, u =36 km/h = 10 m/s
Final speed of the three-wheeler, v =0 m/s
Time, t = 4 s
Mass of the three-wheeler, m =400 kg
Mass of the driver, m‘ = 65 kg
Total mass of the system, M =400 + 65 = 465 kg
Using the first law of motion, theacceleration (a) of the three-wheeler can be calculated as:
v = u + at
Thenegative sign indicates that the velocity of the three-wheeler is decreasingwith time.
UsingNewton’s second law of motion, the net force acting on the three-wheeler can becalculated as:
F = Ma
=465 × (–2.5) = –1162.5 N
Thenegative sign indicates that the force is acting against the direction ofmotion of the three-wheeler.