MENU
Question -

The velocity-time graph of a particle in one-dimensional motion is shownin the figure.

(a) x (t2) = x (t1) + v (t1) (t2 –t1) + (1/2) a(t2 – t1)2

(b) v(t2) = v(t1) + a(t2 – t1)

(c) aaverage =  [ x(t2) – x (t1)]/(t2 – t1)

(d)  aaverage =  [ v(t2) – v (t1)]/(t2 – t1)

(e) x (t2) = x (t1) + v (t2 – t1)+ (1/2) aav (t2 – t1)2

(d) x(t2) – x (t1) = Area under the v-t curve bounded by t- axis and thedotted lines.



Answer -

The graph has anon-uniform slope between the intervals t1 and t2 (sincethe graph is not a straight line). The equations (a), (b) and (e) does notdescribe the motion of the particle. Only the relations (c), (d) and (f) arecorrect.

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
×