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Question -

Provide clear explanations and examples to distinguish between:

( a ) The total length of a path covered by a particle and the magnitudeof displacement over the same interval of time.

( b ) The magnitude of average velocity over an interval of time, and theaverage speed over the same interval. [Average speed of a particle over aninterval of time is defined as the total path length divided by the timeinterval].

In ( a ) and ( b ) compare and find which among the two quantity isgreater.

 When can the given quantities be equal? [For simplicity, considerone-dimensional motion only].      



Answer -

( a ) Let us consideran example of a football, it is passed to player B by player A and theninstantly kicked back to player A along the same path. Now, the magnitude ofdisplacement of the ball is 0 because it has returned to its initial position.However, the total length of the path covered by the ball = AB +BA = 2AB. Hence,it is clear that the first quantity is greater than the second.

( b ) Taking the aboveexample, let us assume that football takes t seconds to cover the totaldistance. Then,

The magnitude of theaverage velocity of the ball over time interval t = Magnitude ofdisplacement/time interval

= 0 / t = 0.

The average speed ofthe ball over the same interval = total length of the path/time interval

= 2AB/t

Thus, the secondquantity is greater than the first.

The above quantitiesare equal if the ball moves only in one direction from one player to another(considering one-dimensional motion).

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