Question -
Answer -
Given
The work done (W) on the system while the gas changes from stateA to state B is 22.3 J
This is an adiabatic process.
Therefore, change in heat is zero.
So,
ΔQ = 0
ΔW = – 22.3 (Since the work is done on the system)
From first law of thermodynamics, we have:
ΔQ = ΔU + ΔW
Where,
ΔU = Change in the internal energy of the gas
Hence,
ΔU = ΔQ – ΔW
= 0 – (-22.3 J)
We get,
ΔU = + 22.3 J
When the gas goes from state A to state B via a process, the netheat absorbed by the system is:
ΔQ = 9.35 cal
= 9.35 x 4.19
On calculation, we get,
= 39.1765 J
Heat absorbed, ΔQ = ΔU + ΔW
Thus,
ΔW = ΔQ – ΔU
= 39.1765 – 22.3
We get,
= 16.8765 J
Hence, 16.88 J of work is done by the system