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Question -

Ablock of mass 25 kg is raised by a 50 kg man in two different ways as shown inFig. 5.19. What is the action on the floor by the man in the two cases? If thefloor yields to a normal force of 700 N, which mode should the man adopt tolift the block without the floor yielding?



Answer -

750N and 250 N in the respective cases; Method (b)

Mass of the block, m = 25kg

Mass of the man, M = 50 kg

Acceleration due to gravity, g = 10 m/s2

Force applied on the block, F =25 × 10 = 250 N

Weight of the man, W = 50 ×10 = 500 N

Case (a): When the man lifts the blockdirectly

Inthis case, the man applies a force in the upward direction. This increases hisapparent weight.

Action on the floor by the man = 250 + 500 =750 N

Case (b): When the man lifts the block usinga pulley

Inthis case, the man applies a force in the downward direction. This decreaseshis apparent weight.

Action on the floor by the man = 500 – 250 =250 N

Ifthe floor can yield to a normal force of 700 N, then the man should adopt thesecond method to easily lift the block by applying lesser force.

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