Question -
Answer -
Speed of the water stream, v =15 m/s
Cross-sectional area of the tube, A =10–2 m2
Volumeof water coming out from the pipe per second,
V = Av = 15 × 10–2 m3/s
Density of water, ρ = 103 kg/m3
Mass of water flowing out through the pipeper second = ρ × V = 150 kg/s
Thewater strikes the wall and does not rebound. Therefore, the force exerted bythe water on the wall is given by Newton’s second law of motion as:
F =Rate of change of momentum 