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Question -

A mild steel wire of length 1.0 m and cross-sectional area 0.50 x 10-2 cm2 is stretched, well within its elastic limit, horizontally between two pillars. Amass of 100g is suspended from the mid-point of the wire. Calculate the depression at the mid-point.



Answer -

Let AB be a mild steel wire of length 2L = lm and its cross-section areaA = 0.50 x 10-2 cm2. A mass m = 100 g = 0.1 kg issuspended at mid-point C of wire as shown in figure. Let x be the
depression at mid-point i.e., CD = x

 

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