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Question -

A constant retarding force of 50 N isapplied to a body of mass 20 kg moving initially with a speed of 15 ms–1.How long does the body take to stop?



Answer -

Retarding force, F = –50 N

Mass of the body, m = 20 kg

Initial velocity of the body, u =15 m/s

Final velocity of the body, v =0

Using Newton’s second law of motion, theacceleration (a) produced in the body can be calculated as:

F = ma

–50 = 20 × a

Using the first equation of motion, the time(t) taken by the body to come to rest can be calculated as:

v = u + at

 =6 s

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