The Total solution for NCERT class 6-12
Mass of the girl, m = 50 kg
Diameterof the heel, d = 1 cm = 0.01 m
Radius ofthe heel, r
Area ofthe heel
= π (0.005)2
= 7.85 ×10–5 m2
Forceexerted by the heel on the floor:
F = mg
= 50 ×9.8
= 490 N
Pressureexerted by the heel on the floor:
= 6.24 ×106 N m–2
Therefore,the pressure exerted by the heel on the horizontal floor is6.24 × 106 Nm–2.