Question -
Answer -
The first five membersof each homologous series beginning with the given compounds are shown asfollows:
(a)
H–COOH : Methanoic acid
CH3–COOH :Ethanoic acid
CH3–CH2–COOH: Propanoic acid
CH3–CH2–CH2–COOH: Butanoic acid
CH3–CH2–CH2–CH2–COOH: Pentanoic acid
(b)
CH3COCH3 :Propanone
CH3COCH2CH3 :Butanone
CH3COCH2CH2CH3 :Pentan-2-one
CH3COCH2CH2CH2CH3 :Hexan-2-one
CH3COCH2CH2CH2CH2CH3 :Heptan-2-one
(c)
H–CH=CH2 :Ethene
CH3–CH=CH2 :Propene
CH3–CH2–CH=CH2 :1-Butene
CH3–CH2–CH2–CH=CH2 :1-Pentene
CH3–CH2–CH2–CH2–CH=CH2 :1-Hexene