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Question -

Describe the hybridisation in case of PCl5. Why are the axial bondslonger as compared to equatorial bonds?



Answer -

The ground state andexcited state outer electronic configurations of phosphorus (Z = 15) are:

Phosphorus atom is sp3d hybridized in theexcited state. These orbitals are filled by the electron pairs donated by fiveCl atoms as:

PCl5

The five sp3d hybrid orbitals aredirected towards the five corners of the trigonal bipyramidals. Hence, thegeometry of PCl5 can be represented as:

There are five P–Cl sigma bonds in PCl5. Three P–Cl bonds lie inone plane and make an angle of 120° with each other. These bonds are calledequatorial bonds.

The remaining two P–Clbonds lie above and below the equatorial plane and make an angle of 90° withthe plane. These bonds are called axial bonds.

Asthe axial bond pairs suffer more repulsion from the equatorial bond pairs,axial bonds are slightly longer than equatorial bonds.

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