Question -
Answer -
LetтАЩs assume A1,A2, A3, A4, and A5┬аto be fivenumbers between 8 and 26 such that 8, A1, A2, A3,A4, A5, 26 are in an A.P.
Here we have,
a┬а= 8,┬аb┬а= 26,┬аn┬а=7
So,
26 = 8 + (7 тАУ 1)┬аd
6d┬а= 26 тАУ8 = 18
d┬а= 3
Now,
A1┬а=┬аa┬а+┬аd┬а=8 + 3 = 11
A2┬а=┬аa┬а+2d┬а= 8 + 2 ├Ч 3 = 8 + 6 = 14
A3┬а=┬аa┬а+3d┬а= 8 + 3 ├Ч 3 = 8 + 9 = 17
A4┬а=┬аa┬а+4d┬а= 8 + 4 ├Ч 3 = 8 + 12 = 20
A5┬а=┬аa┬а+5d┬а= 8 + 5 ├Ч 3 = 8 + 15 = 23
Therefore, therequired five numbers between 8 and 26 are 11, 14, 17, 20, and 23.