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Question -

Find where 0 (zero) is a term of the AP 40, 37, 34, 31, тАжтАж [CBSE 2014]



Answer -

AP 40, 37, 34, 31, тАж..
Here a = 40, d = -3
Let Tn┬а= 0
Tn┬а= a + (n тАУ 1) d
=> 0 = 40 + (n тАУ 1) (-3)
=> 0 = 40 тАУ 3n + 3
=> 3n = 43
=> n =┬а
433┬аwhich is infraction
There is no term which is 0

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