The Total solution for NCERT class 6-12
Numbers divisible byboth 2 and 5 are 110, 120, 130, ………. , 990Here a = 110, x = 120 – 110 = 10an = 990As a + (n – 1) d = 990110 + (n – 1) (10) = 990(n – 1) (10) = 990 – 110 = 880n – 1 = 88n = 88 + 1 = 89