The Total solution for NCERT class 6-12
First 3-digit numberwhich is divisible by 9 = 108and last 3-digit number = 999d= 9a + (n – 1) d = 999=> 108 + (n – 1) x 9 = 999=> (n – 1) d = 999 – 108=> (n – 1) x 9 = 891=> n – 1 = 99=> n = 99 + 1 = 100Number of terms = 100